Integrand size = 21, antiderivative size = 102 \[ \int \cot ^2(c+d x) (a+a \sec (c+d x))^n \, dx=-\frac {2^{-1+n} \operatorname {AppellF1}\left (-\frac {1}{2},-2+n,1,\frac {1}{2},-\frac {a-a \sec (c+d x)}{a+a \sec (c+d x)},\frac {a-a \sec (c+d x)}{a+a \sec (c+d x)}\right ) \cot (c+d x) \left (\frac {1}{1+\sec (c+d x)}\right )^{-1+n} (a+a \sec (c+d x))^n}{d} \]
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Time = 0.06 (sec) , antiderivative size = 102, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.048, Rules used = {3974} \[ \int \cot ^2(c+d x) (a+a \sec (c+d x))^n \, dx=-\frac {2^{n-1} \cot (c+d x) \left (\frac {1}{\sec (c+d x)+1}\right )^{n-1} (a \sec (c+d x)+a)^n \operatorname {AppellF1}\left (-\frac {1}{2},n-2,1,\frac {1}{2},-\frac {a-a \sec (c+d x)}{\sec (c+d x) a+a},\frac {a-a \sec (c+d x)}{\sec (c+d x) a+a}\right )}{d} \]
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Rule 3974
Rubi steps \begin{align*} \text {integral}& = -\frac {2^{-1+n} \operatorname {AppellF1}\left (-\frac {1}{2},-2+n,1,\frac {1}{2},-\frac {a-a \sec (c+d x)}{a+a \sec (c+d x)},\frac {a-a \sec (c+d x)}{a+a \sec (c+d x)}\right ) \cot (c+d x) \left (\frac {1}{1+\sec (c+d x)}\right )^{-1+n} (a+a \sec (c+d x))^n}{d} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(893\) vs. \(2(102)=204\).
Time = 3.28 (sec) , antiderivative size = 893, normalized size of antiderivative = 8.75 \[ \int \cot ^2(c+d x) (a+a \sec (c+d x))^n \, dx=\frac {(a (1+\sec (c+d x)))^n \left (-2^n \cot \left (\frac {1}{2} (c+d x)\right ) \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},n,\frac {1}{2},\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) \left (\cos (c+d x) \sec ^2\left (\frac {1}{2} (c+d x)\right )\right )^n \left (\cos ^2\left (\frac {1}{2} (c+d x)\right ) \sec (c+d x)\right )^n (1+\sec (c+d x))^{-n}+2^n \operatorname {Hypergeometric2F1}\left (\frac {1}{2},n,\frac {3}{2},\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) \left (\cos (c+d x) \sec ^2\left (\frac {1}{2} (c+d x)\right )\right )^n \left (\cos ^2\left (\frac {1}{2} (c+d x)\right ) \sec (c+d x)\right )^n (1+\sec (c+d x))^{-n} \tan \left (\frac {1}{2} (c+d x)\right )-\frac {60 \operatorname {AppellF1}\left (\frac {1}{2},n,1,\frac {3}{2},\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) \cos ^2\left (\frac {1}{2} (c+d x)\right ) \cos (c+d x) \sin (c+d x) \left (3 \operatorname {AppellF1}\left (\frac {1}{2},n,1,\frac {3}{2},\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )-2 \left (\operatorname {AppellF1}\left (\frac {3}{2},n,2,\frac {5}{2},\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )-n \operatorname {AppellF1}\left (\frac {3}{2},1+n,1,\frac {5}{2},\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )\right ) \tan ^2\left (\frac {1}{2} (c+d x)\right )\right )}{45 \operatorname {AppellF1}\left (\frac {1}{2},n,1,\frac {3}{2},\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )^2 \cos ^2\left (\frac {1}{2} (c+d x)\right ) (1+2 n-2 n \cos (c+d x)+\cos (2 (c+d x)))+6 \operatorname {AppellF1}\left (\frac {1}{2},n,1,\frac {3}{2},\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) \sin ^2\left (\frac {1}{2} (c+d x)\right ) \left (-5 \operatorname {AppellF1}\left (\frac {3}{2},n,2,\frac {5}{2},\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) (1+2 n-2 (2+n) \cos (c+d x)+\cos (2 (c+d x)))+5 n \operatorname {AppellF1}\left (\frac {3}{2},1+n,1,\frac {5}{2},\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) (1+2 n-2 (2+n) \cos (c+d x)+\cos (2 (c+d x)))-48 \left (2 \operatorname {AppellF1}\left (\frac {5}{2},n,3,\frac {7}{2},\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )-2 n \operatorname {AppellF1}\left (\frac {5}{2},1+n,2,\frac {7}{2},\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )+n (1+n) \operatorname {AppellF1}\left (\frac {5}{2},2+n,1,\frac {7}{2},\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )\right ) \cot (c+d x) \csc (c+d x) \sin ^4\left (\frac {1}{2} (c+d x)\right )\right )+40 \left (\operatorname {AppellF1}\left (\frac {3}{2},n,2,\frac {5}{2},\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )-n \operatorname {AppellF1}\left (\frac {3}{2},1+n,1,\frac {5}{2},\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )\right )^2 \cos (c+d x) \sin ^2\left (\frac {1}{2} (c+d x)\right ) \tan ^2\left (\frac {1}{2} (c+d x)\right )}\right )}{2 d} \]
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\[\int \cot \left (d x +c \right )^{2} \left (a +a \sec \left (d x +c \right )\right )^{n}d x\]
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\[ \int \cot ^2(c+d x) (a+a \sec (c+d x))^n \, dx=\int { {\left (a \sec \left (d x + c\right ) + a\right )}^{n} \cot \left (d x + c\right )^{2} \,d x } \]
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\[ \int \cot ^2(c+d x) (a+a \sec (c+d x))^n \, dx=\int \left (a \left (\sec {\left (c + d x \right )} + 1\right )\right )^{n} \cot ^{2}{\left (c + d x \right )}\, dx \]
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\[ \int \cot ^2(c+d x) (a+a \sec (c+d x))^n \, dx=\int { {\left (a \sec \left (d x + c\right ) + a\right )}^{n} \cot \left (d x + c\right )^{2} \,d x } \]
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\[ \int \cot ^2(c+d x) (a+a \sec (c+d x))^n \, dx=\int { {\left (a \sec \left (d x + c\right ) + a\right )}^{n} \cot \left (d x + c\right )^{2} \,d x } \]
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Timed out. \[ \int \cot ^2(c+d x) (a+a \sec (c+d x))^n \, dx=\int {\mathrm {cot}\left (c+d\,x\right )}^2\,{\left (a+\frac {a}{\cos \left (c+d\,x\right )}\right )}^n \,d x \]
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